How do you add $(9 - 4 i) + (- 2 + i)$ $(9-4i)+(-2+i)$ in trigonometric form?

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How do you add $(9 - 4 i) + (- 2 + i)$ $(9-4i)+(-2+i)$ in trigonometric form?

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Answer 1 · 2018-05-13T11:30:17

$(9 - 4 i) + (- 2 + i) = 7 - 3 i$ $(9-4i) +(-2+i) = 7-3i$

Explanation:

There's no reason to do it in trigonometric form. The trigonometric form of complex numbers can be used mostly when we have to multiply or divide two complex numbers.

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How do you add $(9 - 4 i) + (- 2 + i)$ $(9-4i)+(-2+i)$ in trigonometric form?

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Explanation:

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How do you add $(9 - 4 i) + (- 2 + i)$ $(9-4i)+(-2+i)$ in trigonometric form?