How do you calculate $(2+3i)/(-3-2i)$ ?

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Answer 1 · 2017-02-18T08:06:58

$-12/13 -5/13i$

Use the conjugate of the denominator to multiply by one:
$(2+3i)/(-3-2i) = (2+3i)/(-3-2i) * (-3+2i)/(-3+2i) = (-6+4i-9i+6i^2)/(9-4i^2)$

Remember that $i^2 = -1$

Simplify and combine like-terms :
$(-6+4i-9i-6)/(9+4) =(-12-5i)/13 = -12/13 -5/13i$

How do you calculate (2+3i)/(-3-2i)(2+3i)/(-3-2i)?