How do you convert $- 2 - 7 i$ $-2 - 7i$ to polar form?

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Answer 1 · 2018-06-24T06:26:26

$Polar form = (r, θ) = (7.28, {254.05}^{\circ})$ $color(green)("Polar form " = (r, theta) = (7.28, 254.05^@)$

$z = - 2 - i 7$ $z = -2 - i 7$

$r = \sqrt{- 2^{2} + - 7^{2}} = \sqrt{53} = 7.28$ $r = sqrt (-2^2 + -7^2) = sqrt 53 = 7.28$

$θ = {tan}^{- 1} (- \frac{7}{- 2}) = 3.5 = 74.05$ $theta = tan ^ -1 (-7 / -2) = 3.5 = 74.05$

Point lies in the third quadrant.

$Hence θ = 180 + 74.05 = {254.05}^{\circ}$ $"Hence " theta = 180 + 74.05 = 254.05^@$

$Polar form = (r, θ) = (7.28, {254.05}^{\circ})$ $color(green)("Polar form " = (r, theta) = (7.28, 254.05^@)$

How do you convert −2−7i-2 - 7i to polar form?