How do you convert $3 + 3 i$ $3 + 3i$ to polar form?

Question

How do you convert $3 + 3 i$ $3 + 3i$ to polar form?

1 Answer

Impact of this question

10454 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-04-26T10:51:57

$(3 \sqrt{2}, \frac{π}{4})$ $(3sqrt2 , pi/4)$

Explanation:

Using the formulae that links Cartesian to Polar coordinates.

$∙ r^{2} = x^{2} + y^{2} \Rightarrow r = \sqrt{x^{2} + y^{2}}$ $• r^2 = x^2+y^2 rArr r=sqrt(x^2+y^2)$

$∙ θ = {tan}^{- 1} (\frac{y}{x})$ $• theta = tan^-1(y/x)$

here x = 3 and y = 3

$\Rightarrow r = \sqrt{3^{2} + 3^{2}} = \sqrt{18} = 3 \sqrt{2}$ $rArr r = sqrt(3^2+3^2)=sqrt18 = 3sqrt2$

and $θ = {tan}^{- 1} (\frac{3}{3}) = {tan}^{- 1} (1) = \frac{π}{4}$ $theta = tan^-1(3/3)=tan^-1(1)=pi/4$

$\Rightarrow 3 + 3 i = (3 \sqrt{2}, \frac{π}{4}) in polar form$ $rArr 3 + 3i = (3sqrt2, pi/4)" in polar form "$

Science

Math

Humanities

... and beyond

How do you convert $3 + 3 i$ $3 + 3i$ to polar form?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you convert 3+3i3 + 3i to polar form?

1 Answer

Explanation:

Related questions

Impact of this question

How do you convert $3 + 3 i$ $3 + 3i$ to polar form?