How do you convert $- 3 + 4 i$ $-3+4i$ to polar form?

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How do you convert $- 3 + 4 i$ $-3+4i$ to polar form?

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Answer 1 · 2016-04-22T11:21:19

In polar form $Z = 5 (cos 2.214 + i sin 2.214)$ $Z= 5(cos 2.214+ i sin 2.214)$

Explanation:

$Z = - 3 + 4 i$ $Z= -3 +4i$ Modulas $(Z) = \sqrt{- 3^{2} + 4^{2}} = 5$ $(Z) = sqrt( -3^2+4^2) =5$ Argument $(Z) = π - {tan}^{- 1} (\frac{4}{3}) = 2.214$ $(Z)=pi - tan^-1(4/3) =2.214$ (radian) The point lies on the 2nd quaqdrant.
In polar form $Z = 5 (cos 2.214 + i sin 2.214)$ $Z= 5(cos 2.214+ i sin 2.214)$ [Ans]

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How do you convert $- 3 + 4 i$ $-3+4i$ to polar form?

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Explanation:

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How do you convert −3+4i-3+4i to polar form?

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How do you convert $- 3 + 4 i$ $-3+4i$ to polar form?