How do you convert 3+ j53+j5 to polar form?

1 Answer
Sep 6, 2016

(sqrt34,1.03)(34,1.03)

Explanation:

To convert from color(blue)"cartesian to polar form"cartesian to polar form

That is (x,y)to(r,theta)(x,y)(r,θ)

color(orange)"Reminder " color(red)(|bar(ul(color(white)(a/a)color(black)(r=sqrt(x^2+y^2))color(white)(a/a)|)))

and color(red)(|bar(ul(color(white)(a/a)color(black)(theta=tan^-1(y/x))color(white)(a/a)|)))

here x = 3 and y = 5

rArrr=sqrt(3^2+5^2)=sqrt(9+25)=sqrt34

Now 3 + 5j is in the 1st quadrant so we must ensure that theta is in the 1st quadrant.

theta=tan^-1(5/3)=1.03" radians"larr " in 1st quadrant"

Thus (3,5)to(sqrt34,1.03)to(sqrt34,59.04^@)