How do you convert 3+ j53+j5 to polar form?
1 Answer
Sep 6, 2016
Explanation:
To convert from
color(blue)"cartesian to polar form"cartesian to polar form That is
(x,y)to(r,theta)(x,y)→(r,θ)
color(orange)"Reminder " color(red)(|bar(ul(color(white)(a/a)color(black)(r=sqrt(x^2+y^2))color(white)(a/a)|))) and
color(red)(|bar(ul(color(white)(a/a)color(black)(theta=tan^-1(y/x))color(white)(a/a)|))) here x = 3 and y = 5
rArrr=sqrt(3^2+5^2)=sqrt(9+25)=sqrt34 Now 3 + 5j is in the 1st quadrant so we must ensure that
theta is in the 1st quadrant.
theta=tan^-1(5/3)=1.03" radians"larr " in 1st quadrant" Thus
(3,5)to(sqrt34,1.03)to(sqrt34,59.04^@)