How do you convert 3√2−3√2i to polar form?

1 Answer
Binayaka C.
Apr 17, 2016

In Polar form the equation is 6(cos(−0.785)+isin(−0.785))

Explanation:

Z=3√2−3√2i so Modulas Z=√(3√2)2+(−3√2)2=6
Argument z=θ=tan−1(−3√23√2)=tan1(−1)=−0.785radian So in Polar form the equation is 6(cos(−0.785)+isin(−0.785))

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