How do you convert $3 x + 2 y = 16$ $3x+2y=16$ to polar form?

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How do you convert $3 x + 2 y = 16$ $3x+2y=16$ to polar form?

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Answer 1 · 2016-04-11T12:16:18

In polar form : $3 cos θ + 4 sin θ = \frac{16}{r}$ $3 cos theta+4sin theta=16/r$

Explanation:

In polar form we know $r^{2} = x^{2} + y^{2}; x = r cos θ; y = r sin θ and θ = {tan}^{- 1} (\frac{y}{x})$ $r^2=x^2+y^2 ; x=rcostheta ;y =rsin theta and theta=tan^-1(y/x)$ So $3 \cdot r \cdot cos θ + 4 \cdot r \cdot sin θ = 16 or 3 cos θ + 4 sin θ = \frac{16}{r}$ $3*r*cos theta+4*r*sin theta=16 or 3 cos theta+4sin theta=16/r$ [Ans]

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How do you convert $3 x + 2 y = 16$ $3x+2y=16$ to polar form?

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Science

Math

Humanities

... and beyond

How do you convert 3x+2y=16 3x+2y=16 to polar form?

1 Answer

Explanation:

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How do you convert $3 x + 2 y = 16$ $3x+2y=16$ to polar form?