Question

How do you convert `-8 +8i` to polar form?

Answer 1

In polar form :`Z= -8+8i = 8sqrt2(cos (3*pi/4) +i sin (3*pi/4))`

Explanation:

Let `Z= -8 +8i`; Modulus: `|Z| = sqrt ( (-8)^2+ 8^2) = sqrt 128 = 8 sqrt 2` Argument: `theta` is in 2nd quadrant `:.theta = pi - tan^-1(8/8) = pi-pi/4 = (3*pi)/4 :. Z= -8+8i = 8sqrt2(cos (3*pi/4) +i sin (3*pi/4))`[Ans]