Question

How do you convert cartesian `(-sqrt7, 0)` to polar form?

Answer 1

Cartesian form `(x, y) = (-sqrt 7, 0) = (r cos theta, r sin theta)` transforms to the polar form `(r, theta ) = ( sqrt 7, pi )`.

Explanation:

`x=-sqrt 7 and y=0`.

`r=sqrt(x^2+y^2)=sqrt 7. cos theta = x/r=-1 and sin theta =y/r=0`
So, `theta=pi`..