How do you convert $x^{2} + y^{2} + 2 x = 0$ $x^2 + y^2 +2x = 0$ to polar form?

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Answer 1 · 2016-06-24T13:56:29

$r + 2 cos (θ) = 0$ $r+2 cos(theta)= 0$

Substituting the pass equations

${ (x = r cos(theta)), (y = r sin(theta)) :}$

we have

$r^2cos(theta)^2+r^2sin(theta)^2+2r cos(theta)=0$

Simplifying

$r+2 cos(theta)= 0$

See figure attached

enter image source here

How do you convert x^2 + y^2 +2x = 0x2+y2+2x=0x^2 + y^2 +2x = 0 to polar form?