How do you convert $x^{2} + y^{2} = 36$ $x^2 + y^2 = 36$ to polar form?

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Answer 1 · 2016-06-23T18:28:29

$r = 6$ $r = 6$

From the pass equations

${(x = r cos(theta)), (y = r sin(theta)) :}$

$(r cos(theta))^2+(r sin(theta))^2=6^2-> r^2= 6^2->r = 6$

How do you convert x^2 + y^2 = 36x2+y2=36x^2 + y^2 = 36 to polar form?