How do you convert $y = x^{2}$ $y = x^2$ to polar form?

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Answer 1 · 2016-06-23T11:39:48

$r = tan θ sec θ$ $r = tan theta sec theta$

$x = r cos θ$ $x = r cos theta$
$y = r sin θ$ $y = r sin theta$

$r sin θ = {(r cos θ)}^{2} = r^{2} {cos}^{2} θ$ $r sin theta = (r cos theta)^2 = r^2 cos^2 theta$

$sin θ = r {cos}^{2} θ$ $sin theta = r cos^2 theta$

$r = \frac{sin θ}{{cos}^{2} θ} = tan θ sec θ$ $r = (sin theta)/(cos^2 theta) = tan theta sec theta$

How do you convert y=x2y = x^2 to polar form?