How do you convert $z = 55$ $z= 55$ to polar form?

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Answer 1 · 2016-09-11T12:39:55

$z = 55 (cos (0) + i sin (0))$ $z = 55 (cos(0) + isin(0))$

The polar form of $z$ $z$ looks like

$z = r (cos θ + i sin θ)$ $z = r(costheta + isintheta)$

where $r$ $r$ and $θ$ $theta$ are real numbers to be found

From Pythagorean's Theorem,
$r = \sqrt{55^{2} + 0^{2}} = 55$ $r = sqrt{55^2 + 0^2} = 55$

From trigonometry,
$θ = {tan}^{- 1} (\frac{0}{55}) = 0$ $theta = tan^{-1}(0/55) = 0$

How do you convert z=55z= 55 to polar form?