How do you decompose $\frac{5 m - 4}{m^{2} - 4}$ $(5m-4)/(m^2-4)$ into partial fractions?

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Answer 1 · 2018-02-01T20:46:45

$\frac{5 m - 4}{m^{2} - 4}$ $(5m−4)/(m^2−4)$

$\frac{5 m - 4}{(m - 2) (m + 2)}$ $(5m−4)/((m-2)(m+2))$

decompose into partial fractions,

$\frac{5 m - 4}{(m - 2) (m + 2)} = \frac{A}{m + 2} + \frac{B}{m - 2}$ $(5m−4)/((m-2)(m+2))=A/(m+2) + B/(m-2)$

Where A and B are arbitrary constants whose value is found accordingly.

-Sahar :)

How do you decompose 5m−4m2−4(5m-4)/(m^2-4) into partial fractions?