How do you divide 2i−47i−2 in trigonometric form?

1 Answer
Leland Adriano Alejandro
Jul 25, 2016

2i−47i−2=2√26553[cos47.48∘+i⋅sin47.48∘]

Explanation:

The solution:

2i−4=
√4+16[cos(tan−1(−12))+i⋅sin(tan−1(−12))]
√20[cos(tan−1(−12))+i⋅sin(tan−1(−12))]

7i−2=
√4+49[cos(tan−1(−72))+i⋅sin(tan−1(−72))]

2i−47i−2=
√20√53[cos(tan−1(−12)−tan−1(−12))+i⋅sin(tan−1(−12)−tan−1(−12))]

2i−47i−2=2√26553[cos47.48∘+i⋅sin47.48∘]

God bless.....I hope the explanation is useful.

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