How do you divide $\frac{6 i + 4}{- 2 i - 1}$ $( 6i+4) / (-2i -1 )$ in trigonometric form?

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How do you divide $\frac{6 i + 4}{- 2 i - 1}$ $( 6i+4) / (-2i -1 )$ in trigonometric form?

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Answer 1 · 2016-01-20T15:52:23

evaluate the following:
$C_{3} = \frac{\sqrt{52}}{\sqrt{5}} ∠ (26)$ $C_3 = sqrt(52)/sqrt(5) angle(26)$
$C_{3} = \sqrt{\frac{52}{5}} cos 26 + i \sqrt{\frac{52}{5}} cos 26$ $C_3 = sqrt(52/5)cos26 + i sqrt(52/5)cos26$

Explanation:

Use the polar form:
$C_{1} = 4 + 6 i; | C_{1} | = \sqrt{36 + 16}; θ_{1} = {tan}^{_} 1 (\frac{6}{4}) = 89$ $C_1 = 4 + 6i; |C_1| = sqrt(36+16); theta_1 = tan^_1 (6/4) = 89$
$C_{2} = - 1 - 2 i; | C_{2} | = \sqrt{1 + 4}; θ_{2} = {tan}^{_} 1 (\frac{2}{1}) = - 63$ $C_2 = -1 - 2i; |C_2| = sqrt(1+4); theta_2 = tan^_1 (2/1) = -63$
$C_{3} = \frac{\sqrt{52}}{\sqrt{5}} ∠ (89 - 63)$ $C_3 = sqrt(52)/sqrt(5) angle(89-63)$

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How do you divide $\frac{6 i + 4}{- 2 i - 1}$ $( 6i+4) / (-2i -1 )$ in trigonometric form?

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How do you divide $\frac{6 i + 4}{- 2 i - 1}$ $( 6i+4) / (-2i -1 )$ in trigonometric form?