How do you divide $\frac{8 + 7 i}{i}$ $(8+7i)/(i)$ in trigonometric form?

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Answer 1 · 2016-09-19T08:24:22

$\frac{8 + 7 i}{i} = 7 - 8 i$ $(8+7i)/i=7-8i$

$\frac{8 + 7 i}{i}$ $(8+7i)/i$

= $\frac{(8 + 7 i) \times i}{i \times i}$ $((8+7i)×i)/(i×i)$

= $\frac{8 i + 7 i^{2}}{i^{2}}$ $(8i+7i^2)/i^2$

= $\frac{8 i + 7 \times (- 1)}{- 1}$ $(8i+7×(-1))/(-1)$

= $\frac{- 7 + 8 i}{- 1}$ $(-7+8i)/(-1)$

= $7 - 8 i$ $7-8i$

How do you divide (8+7i)/(i) 8+7ii (8+7i)/(i) in trigonometric form?