How do you divide $\frac{i + 2}{9 i + 4}$ $(i+2) / (9i+4)$ in trigonometric form?

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Answer 1 · 2018-06-14T03:17:01

$\frac{2 + i}{4 + i 9} = 0.175 - i 0.144$ $color(blue)((2 + i) / (4 + i9) = 0.175 - i 0.144$

To divide $\frac{2 + i}{4 + i 9}$ $(2 + i) / (4 + i9)$ using trigonometric form.

$z_{1} = (2 + i), z_{2} = (4 + i 9)$ $z_1 = (2 + i), z_2 = (4+ i9)$

$r_{1} = \sqrt{2^{2} + 1^{2}} = \sqrt{5}$ $r_1 = sqrt(2^2 + 1^2) = sqrt5$

$r_{2} = \sqrt{9^{2} + 4^{2}} = \sqrt{97}$ $r_2 = sqrt(9^2 + 4^2) = sqrt97$

$θ_{1} = arctan (\frac{1}{2}) = {26.57}^{\circ}$ $theta_1 = arctan (1/2) = 26.57^@$

$Theta_2 = arctan(9/4) = 66.06^@$

$r_1 / r_2 = sqrt 5 * / sqrt 97 ~~ 0.227$

$z_1 / z_2 = (r_1 / r_2) * (cos (theta_1 - theta_2) + i sin (theta_1 - theta_2))$

$z_1 / z_2 = (0.227) * (cos (26.57 - 66.06 ) + i sin (26.57 - 66.06 ))$

$z_1 / z_2 = 0.227 * (cos (-39.49) + i sin (-39.49)) = 0.227 (0.772 - i 0.636)$

$color(blue)((2 + i) / (4 + i9) = 0.175 - i 0.144$

How do you divide (i+2) / (9i+4)i+29i+4(i+2) / (9i+4) in trigonometric form?