How do you draw the graph of direct variation that includes the point (1,6) and write the equation of the line?
1 Answer
Aug 12, 2017
Explanation:
"a direct variation equation is of the form"
y=kxlarr" k is the constant of variation"
"to find k use the given condition"
(1,6)toy=6" when "x=1
y=kxrArrk=y/x=6/1=6
"equation is " color(red)(bar(ul(|color(white)(2/2)color(black)(y=6x)color(white)(2/2)|)))
"this is a linear equation, that is it's graph is a straight line"
"to graph this choose values of x and substitute into the "
"equation for corresponding values of y"
((ulx,uly),(-1,-6),(0,0),(1,6))
"plot the points "(-1,-6),(0,0),(1,6)
"and draw a straight line through them"
graph{6x [-11.1, 11.1, -5.54, 5.56]}