Question

How do you draw the graph of `y=-tanx` for `0<=x<2pi`?

Answer 1

See the required graph, in-between `x = 0 and x = 2pi`.

Explanation:

For x in `( 0, 2pi )`, y= 0, at `x = 0, pi, 2pi`
,
There are two asymptotes `x = pi/2 and x = (3/2)pi`, within the

interval.

The graph is not on uniform scale, for better visual effect.

graph{ (y+tan x)(x+0y)(x-2pi+0y) = 0[-0.1 6.3 -16 16]}