How do you evaluate $2 (3) + 12 - (4 \cdot 3)$ $2( 3) + 12- ( 4\cdot 3)$ ?

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Answer 1 · 2018-03-11T08:10:17

$2 (3) + 12 - (4 \cdot 3) = 6$ $2(3)+12-(4*3)=6$

We evaluate this using the order of operations:

In this case we start by evaluating the parenthesis:

$2 (3) + 12 - (4 \cdot 3) = 2 \cdot 3 + 12 - 12$ $2(3)+12-(4*3)=2*3+12-12$

Next we evaluate multiplication:

$6 + 12 - 12$ $6+12-12$

And finally, we do addition and subtraction:

$6 + 12 - 12 = 18 - 12 = 6$ $6+12-12=18-12=6$

How do you evaluate 2(3)+12−(4⋅3)2( 3) + 12- ( 4\cdot 3)?