How do you evaluate ${(- 2)}^{5}$ $(-2)^5$ ?

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How do you evaluate ${(- 2)}^{5}$ $(-2)^5$ ?

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Answer 1 · 2018-03-07T03:51:10

-32

Explanation:

$- 2 \cdot - 2 = 4$ $-2 * -2 = 4$ or $(- 2^{2})$ $(-2^2)$
$4 \cdot - 2 = - 8$ $4 * -2 = -8$ or $(- 2^{3})$ $(-2^3)$
$- 8 \cdot - 2 = 16$ $-8 * -2 = 16$ or $(- 2^{4})$ $(-2^4)$
$16 \cdot - 2 = - 32$ $16* -2 = -32$ or $(- 2^{5})$ $(-2^5)$

Answer 2 · 2018-03-07T03:53:54

$- 32$ $-32$

Explanation:

The exponent represents the number of times that $(- 2)$ $(-2)$ is multiplied by itself.

The easiest way to evaluate this, is to rewrite it out like such:

$(- 2) (- 2) (- 2) (- 2) (- 2)$ $(-2)(-2)(-2)(-2)(-2)$

From here it is just simple multiplication:

$(- 2) (- 2) (- 2) (- 2) (- 2)$ $(-2)(-2)(-2)(-2)(-2)$

$(4) (- 2) (- 2) (- 2)$ $(4)(-2)(-2)(-2)$

$(4) (4) (- 2)$ $(4)(4)(-2)$

$(16) (- 2)$ $(16)(-2)$

$(- 32)$ $(-32)$

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How do you evaluate ${(- 2)}^{5}$ $(-2)^5$ ?

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