How do you evaluate #-3( 7- 11)#?

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Answer 1 · 2018-03-04T02:31:20

The result is #12#.

First, do the subtraction that's inside the parentheses (in red). After that, do the multiplication of the two numbers (in blue).

#color(white)=-3(color(red)(7-11))#

#=-3(color(red)(-4))#

#=color(blue)-color(blue)(3*-4)#

#=color(red)cancelcolor(blue)-color(blue)(3*)color(red)cancelcolor(blue)-color(blue)4#

#=color(blue)(3*4)#

#=12#