How do you evaluate $4 - [1 + 2 {(3 - 4)}^{2}]$ $4- [ 1+ 2( 3- 4) ^ { 2} ]$ ?

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Answer 1 · 2017-03-28T17:18:47

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$4 - [1 + 2 {(3 - 4)}^{2}] = 4 - [1 + 2 {(- 1)}^{2}] = 4 - [1 + 2 (1)] = 4 - 3 = 1$ $4-[1+2(3-4)^2]=4-[1+2(-1)^2]=4-[1+2(1)]=4-3=1$

How do you evaluate 4−[1+2(3−4)2]4- [ 1+ 2( 3- 4) ^ { 2} ]?