How do you evaluate e7π4ie3π2i using trigonometric functions?

1 Answer
Apr 9, 2016

0.317+0.921i

Explanation:

According to Euler's theorem,

eix=cosx+isinx

Therefore, using values for x from the question,

x=7π4
e7π4i=cos(7π4)+isin(7π4)
=cos315+isin315
=0.667+0.745i

x=3π2
e3π2i=cos(3π2)+isin(3π2)
=cos270+isin270
=0.9840.176i

Put both these values back into the original question,

e7π4ie3π2i=0.667+0.745i0.984+0.176i
=0.317+0.921i