How do you evaluate $(- \frac{3}{5}) (- \frac{8}{15}) \div (- 1 \frac{1}{5})$ $(- \frac { 3} { 5} ) ( - \frac { 8} { 15} ) \div ( - 1\frac { 1} { 5} )$ ?

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Answer 1 · 2018-03-06T05:07:11

$- \frac{4}{15}$ $-4/15$

$(- \frac{3}{5}) (- \frac{8}{15}) \div (- 1 \frac{1}{5})$ $(-3/5)(-8/15)-:(-1 1/5)$

Let's take that right fraction and convert it into an improper form:

$(- \frac{3}{5}) (- \frac{8}{15}) \div (- \frac{6}{5})$ $(-3/5)(-8/15)-:(-6/5)$

When dividing by a fraction, we can multiply by its reciprocal:

$(- \frac{3}{5}) (- \frac{8}{15}) (- \frac{5}{6})$ $(-3/5)(-8/15)(-5/6)$

We have some opportunities to cancel:

$(cancel(-)cancel3/cancel5)(cancel(-)cancel8^4/15)(-cancel5/cancel6^cancel2)=-4/15$

How do you evaluate (- \frac { 3} { 5} ) ( - \frac { 8} { 15} ) \div ( - 1\frac { 1} { 5} )(−35)(−815)÷(−115)(- \frac { 3} { 5} ) ( - \frac { 8} { 15} ) \div ( - 1\frac { 1} { 5} )?