How do you evaluate $\root[ 3] { 2187} + 2\root [ 3] { 3}$ ?

Question

2441 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-07-04T16:47:05

$root(3)2187+2root(3)3=11root(3)3$

$root(3)2187+2root(3)3$

= $root(3)(3xx3xx3xx3xx3xx3xx3)+2root(3)3$ )

= $root(3)(ul(3xx3xx3)xxul(3xx3xx3)xx3)+2root(3)3$

= $3xx3xxroot(3)3+2root(3)3$

= $9root(3)3+2root(3)3$

= $11root(3)3$

How do you evaluate \root[ 3] { 2187} + 2\root [ 3] { 3}\root[ 3] { 2187} + 2\root [ 3] { 3}?