How do you express the complex number in trigonometric form $2(cos 180° + i sin 180°)$ ?

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How do you express the complex number in trigonometric form $2(cos 180° + i sin 180°)$ ?

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Answer 1 · 2018-05-07T01:58:15

The complex number is already in trigonometric form

Explanation:

The trigonometric form of a complex number $a+bi$ is $r(costheta+isintheta)$ where $r=sqrt(a^2+b^2)$ and $theta$ satisfies $theta=arccosa"/"r,theta=arcsin b"/"r$

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How do you express the complex number in trigonometric form $2(cos 180° + i sin 180°)$ ?

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How do you express the complex number in trigonometric form 2(cos 180° + i sin 180°)2(cos 180° + i sin 180°)?

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Explanation:

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How do you express the complex number in trigonometric form $2(cos 180° + i sin 180°)$ ?