How do you express the complex number in trigonometric form $3(cos 270° + i sin 270°)$ ?

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Answer 1 · 2015-08-02T18:22:37

3 $e^((i3pi)/2)$ where 3 is the modulus and $(3pi)/2$ is the Argument

270 degrees is $(3pi)/2$ , hence the give expression would be represented as 3 $e^((i3pi)/2)$

How do you express the complex number in trigonometric form 3(cos 270° + i sin 270°) 3(cos 270° + i sin 270°)?