How do you express x^3/[x(x^2+2x+1)]x3x(x2+2x+1) in partial fractions?

1 Answer
Apr 13, 2016

x^3/(x(x^2+2x+1))=1-2/(x+1)+1/(x+1)^2x3x(x2+2x+1)=12x+1+1(x+1)2

Explanation:

This one is relatively simpler and need for detailed solution as given here, does not arise.

x^3/(x(x^2+2x+1))=x^2/(x^2+2x+1)=(x^2+2x+1-(2x+1))/(x^2+2x+1)x3x(x2+2x+1)=x2x2+2x+1=x2+2x+1(2x+1)x2+2x+1

= 1-(2x+1)/(x+1)^212x+1(x+1)2

= 1-(2x+2-1)/(x+1)^212x+21(x+1)2

= 1-(2(x+1))/(x+1)^2+1/(x+1)^212(x+1)(x+1)2+1(x+1)2 or

= 1-2/(x+1)+1/(x+1)^212x+1+1(x+1)2