Question

How do you factor `12y^3+28y-3y-7`?

Answer 1

We can factorise this expression by making Groups of two terms:

`(12y^3+28y)-(3y+7)`

`= 4y(3y + 7) - 1(3y + 7)`

`3y+7` is a common factor to both the terms

`= color(green)((3y+7)(4y - 1)`