How do you factor by grouping #2n^2 + 5n + 2#? Algebra Polynomials and Factoring Factoring by Grouping 1 Answer George C. May 17, 2015 #2n^2 + 5n + 2# #= 2n^2 + 4n + n + 2# #= 2n(n+2)+1(n+2)# #= (2n+1)(n+2)# The 'trick' is the particular separation of #5n# into #4n+n#, which results in the ratio of the first to second coefficients being the same as the ratio of the third to fourth coefficients. Answer link Related questions What is Factoring by Grouping? How do you factor by grouping four-term polynomials and trinomials? Why does factoring polynomials by grouping work? How do you factor #2x+2y+ax+ay#? How do you factor #3x^2+8x+4# by using the grouping method? How do you factor #6x^2-9x+10x-15#? How do you group and factor #4jk-8j^2+5k-10j#? What are the factors of #2m^3+3m^2+4m+6#? How do you factor quadratics by using the grouping method? How do you factor #x^4-2x^3+5x-10#? See all questions in Factoring by Grouping Impact of this question 3859 views around the world You can reuse this answer Creative Commons License