How do you factor by grouping #a^3 - a^2 - 8a + 8#? Algebra Polynomials and Factoring Factoring by Grouping 1 Answer George C. May 24, 2015 #a^3-a^2-8a+8# #=(a^3-a^2)-(8a-8)# #=a^2(a-1)-8(a-1)# #=(a^2-8)(a-1)# #=(a^2-(2sqrt(2))^2)(a-1)# #=(a-2sqrt(2))(a+2sqrt(2))(a-1)# ....using the identity #(p^2-q^2) = (p-q)(p+q)# Answer link Related questions What is Factoring by Grouping? How do you factor by grouping four-term polynomials and trinomials? Why does factoring polynomials by grouping work? How do you factor #2x+2y+ax+ay#? How do you factor #3x^2+8x+4# by using the grouping method? How do you factor #6x^2-9x+10x-15#? How do you group and factor #4jk-8j^2+5k-10j#? What are the factors of #2m^3+3m^2+4m+6#? How do you factor quadratics by using the grouping method? How do you factor #x^4-2x^3+5x-10#? See all questions in Factoring by Grouping Impact of this question 2574 views around the world You can reuse this answer Creative Commons License