How do you factor by grouping #xy+4x-2y-8#?

Question

3867 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-04-15T12:02:43

Try collecting #y# between the first and third term and #4# between the second and the fourth:
#y(x-2)+4(x-2)=# now collect #(x-2)#;
#(x-2)(y+4)#