How do you factor by grouping #y^3+y+2y^2+2#?

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Answer 1 · 2015-05-09T22:31:59

#y^3+y+2y^2+2#

#(y^3+y)+(2y^2+2)#

Factor #y# out of the first term.

#y(y^2+1)#

Factor #2# out of the second term.

#2(y^2+1)#

The common factor is #(y^2+1)# .

#y(y^2+1)+2(y^2+1)# =

#(y+2)(y^2+1)#