How do you factor the expression #16x^4 - 25y^2#? Algebra Polynomials and Factoring Special Products of Polynomials 1 Answer José F. Apr 17, 2016 #color(blue)(a^2-b^2=(a+b)(a-b))# So, #16x^4-25y^2=(4x^2-5y)(4x^2+5y)# Answer link Related questions What are the Special Products of Polynomials? What is a perfect square binomial and how do you find the product? How do you simplify by multiplying #(x+10)^2#? How do you use the special product for squaring binomials to multiply #(1/4t+2 )^2#? How do you use the special product of a sum and difference to multiply #(3x^2+2)(3x^2-2)#? How do you evaluate #56^2# using special products? How do you multiply #(3x-2y)^2#? How do you factor # -8x^2 +32#? How do you factor #x^3-8y^3#? How do you factor # x^3 - 1#? See all questions in Special Products of Polynomials Impact of this question 2058 views around the world You can reuse this answer Creative Commons License