How do you factor #x^3 + 4x^2 - 9x - 6 =0#?

1 Answer
Johnson Z.
Nov 26, 2015

#(x+2)(x+3)(x-3)(2x^2-3)=0#

Explanation:

Whenever you have a polynomial with more than #3# terms, it is always a good idea to group your like terms together:

#x^3+4x^2-9x-6=0#
#x^3-9x+4x^2-6=0#
#x(x^2-9)+2(2x^2-3)=0#
#x(x+3)(x-3)+2(2x^2-3)=0#
#(x+2)(x+3)(x-3)(2x^2-3)=0#

Related questions
See all questions in Factoring by Grouping
Impact of this question
3744 views around the world
You can reuse this answer
Creative Commons License