How do you factor #xy² − xz²#? Algebra Polynomials and Factoring Special Products of Polynomials 1 Answer sente Apr 17, 2016 #xy^2 - xz^2= x(y+z)(y-z)# Explanation: Using the difference of squares formula #a^2-b^2 = (a+b)(a-b)# we have: #xy^2 - xz^2 = x(y^2-z^2) = x(y+z)(y-z)# Answer link Related questions What are the Special Products of Polynomials? What is a perfect square binomial and how do you find the product? How do you simplify by multiplying #(x+10)^2#? How do you use the special product for squaring binomials to multiply #(1/4t+2 )^2#? How do you use the special product of a sum and difference to multiply #(3x^2+2)(3x^2-2)#? How do you evaluate #56^2# using special products? How do you multiply #(3x-2y)^2#? How do you factor # -8x^2 +32#? How do you factor #x^3-8y^3#? How do you factor # x^3 - 1#? See all questions in Special Products of Polynomials Impact of this question 2708 views around the world You can reuse this answer Creative Commons License