How do you find the antiderivative of ∫1x2+10x+21dx?
1 Answer
Oct 12, 2016
Explanation:
1x2+10x+21=1(x+3)(x+7)
1x2+10x+21=14((x+7)−(x+3)(x+3)(x+7))
1x2+10x+21=14(1x+3−1x+7)
So:
∫1x2+10x+21dx=∫14(1x+3−1x+7)dx
∫1x2+10x+21dx=14ln|x+3|+14ln|x+7|+C