How do you find the antiderivative of 1x2+10x+21dx?

1 Answer
Oct 12, 2016

1x2+10x+21dx=14ln|x+3|+14ln|x+7|+C

Explanation:

1x2+10x+21=1(x+3)(x+7)

1x2+10x+21=14((x+7)(x+3)(x+3)(x+7))

1x2+10x+21=14(1x+31x+7)

So:

1x2+10x+21dx=14(1x+31x+7)dx

1x2+10x+21dx=14ln|x+3|+14ln|x+7|+C