How do you find the arc length of the curve $y = e^{x^{2}}$ $y=e^(x^2)$ over the interval [0,1]?

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Answer 1 · 2016-09-01T18:02:42

$\approx 2.12762$ $≈2.12762$ numerical solution

$S = int_0^1 sqrt(1+(y')^2) dx$

$= int_0^1 sqrt(1+(2x e^(x^2))^2) dx$

$≈2.12762$ numerical solution

How do you find the arc length of the curve y=e^(x^2)y=ex2y=e^(x^2) over the interval [0,1]?