How do you find the component form of $v = \frac{1}{2} (3 u + w)$ $v=1/2(3u+w)$ given $u = 2 i - j, w = i + 2 j$ $u=2i-j, w=i+2j$ ?

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Answer 1 · 2017-11-03T19:00:38

$\frac{7}{2} i - j$ $7/2 i - j$

Substituting $u and w$ $u and w$ into $v$ $v$ :

$v = \frac{1}{2} (3 (2 i - j) + i + 2 j) = \frac{1}{2} (6 i - 3 j + i + j)$ $v=1/2(3(2i-j)+i+2j)= 1/2(6i-3j+i+j)$

$\to = \frac{1}{2} (7 i - 2 j) = \frac{7}{2} i - j$ $-> = 1/2(7i-2j)= 7/2i-j$

How do you find the component form of v=12(3u+w)v=1/2(3u+w) given u=2i−j,w=i+2ju=2i-j, w=i+2j?