How do you find the discriminant, describe the number and type of root, and find the exact solution using the quadratic formula given $0.4x^2+x-0.3=0$ ?

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Answer 1 · 2017-02-24T12:27:35

$(-1+-sqrt1.48)/0.8$

Discriminant of the quadratic equation
$ax^2+bx+c=0$ , in the quadratic formula is $sqrt(b^2-4ac)$ .

In the present case a= 0.4, b= 1 and c= -0.3, hence the discriminant would be $sqrt(1-4(0.4)(-0.3) ) = sqrt 1.48$

Exact solution would be x= $(-1+- sqrt 1.48)/(2(0.4)$

= $(-1+-sqrt1.48)/0.8$

How do you find the discriminant, describe the number and type of root, and find the exact solution using the quadratic formula given 0.4x^2+x-0.3=00.4x^2+x-0.3=0?