The Quadratic Formula
Key Questions
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The quadratic formula is used to get the roots of a quadratic equation, if the roots exists at all.
We usually just perform factorization to get the roots of a quadratic equation. However, this is not always possible (especially when the roots are irrational)
The quadratic formula is
x=−b±2√b2−4ac2a
Example 1:
y=x2−3x−4
0=x2−3x−4 ⇒0=(x−4)(x+1)
⇒x=4,x=−1 Using the quadratic formula, let's try to solve the same equation
x=−(−3)±2√(−3)2−4⋅1⋅(−4)2⋅1
⇒x=3±2√9+162
⇒x=3±2√252
⇒x=3+52,x=3−52
⇒x=4,x=−1
Example 2:
y=2x2−3x−5
0=2x2−3x−5 Performing factorization is a little hard for this equation, so let's jump straight to using the quadratic formula
x=−(−3)±2√(−3)2−4⋅2⋅(−5)2⋅2 x=3±2√9+404 x=3±2√494 x=3+74,x=3−74 x=52,x=−1 -
Suppose that you have a function represented by
f(x)=Ax2+Bx+C .We can use the quadratic formula to find the zeroes of this function, by setting
f(x)=Ax2+Bx+C=0 .Technically we can also find complex roots for it, but typically one will be asked to work only with real roots. The quadratic formula is represented as:
−B±√B2−4AC2A=x ... where x represents the x-coordinate of the zero.
If
B2−4AC<0 , we will be dealing with complex roots, and ifB2−4AC≥0 , we will have real roots.As an example, consider the function
x2−13x+12 . Here,A=1,B=−13,C=12. Then for the quadratic formula we would have:
x=13±√(−13)2−4(1)(12)2(1) =13±√169−482=13±112 Thus, our roots are
x=1 andx=12 .For an example with complex roots, we have the function
f(x)=x2+1 . HereA=1,B=0,C=1. Then by the quadratic equation,
x=0±√02−4(1)(1)2(1)=±√−42=±i ... where
i is the imaginary unit, defined by its property ofi2=−1 .In the graph for this function on the real coordinate plane, we will see no zeroes, but the function will have these two imaginary roots.
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The discriminant is part of the quadratic formula.
Quadratic Formula
x=−b±√b2−4ac2a Discriminant
b2−4ac The discriminant tells you the number and types of solutions to a quadratic equation.
b2−4ac=0 , one real solutionb2−4ac>0 , two real solutionsb2−4ac<0 , two imaginary solutions -
Answer:
x=−b±√b2−4ac2a Explanation:
Negative b plus minus the square root of b squared minus 4*a*c over 2*a. To plug something into the quadratic formula the equation needs to be in standard form (
ax2+bx2+c ).hope this helps!