Question

How do you solve the quadratic with complex numbers given `5x^2+8x=-4`?

Answer 1

Use the quadratic formula! :)

"A negative boy couldn't decide on whether to go to a radical party. Since the boy was a square, he lost out on four awesome chicks. When the night was over, it was 2 a. m."

Explanation:

Negative Boy `=>-b`
Decide `=>+-`
Radical `=>sqrt`
Boy ... sqaure `=>b^2`
Lost `=>-`
Four Awesome Chicks `=>4ac`
Over ... 2 a.m. `=> 1/(2a)`

Fun little mnemonic for:

`(-b+-sqrt(b^2-4ac))/(2a)`