How do you solve the quadratic using the quadratic formula given $x^2=-3x+40$ ?

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Answer 1 · 2016-09-23T10:56:10

$x = - 8, 5$

We have: $x^(2) = - 3 x + 40$

$=> x^(2) + 3 x - 40 = 0$

$=> x = (- 3 pm sqrt(3^(2) - 4 (1) (- 40))) / (2 (1))$

$=> x = (- 3 pm sqrt(169)) / (2)$

$=> x = (- 3 pm 13) / (2)$

$=> x = - 8, 5$

Therefore, the solutions to the equation are $x = - 8$ and $x = 5$ .

How do you solve the quadratic using the quadratic formula given x^2=-3x+40x^2=-3x+40?