How do you solve $x^2-10x+15=0$ using the quadratic formula?

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Answer 1 · 2018-04-07T03:52:39

$color(green)(x_+ = 5 + sqrt10), color(indigo)(x_- = 5 - sqrt10$

$"Given equation is " x^2 - 10x + 15 = 0$

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$a = 1, b = -10, c = 15$

Applying quadratic formula,

$x = (-(-10) +- sqrt((-10)^2 - (4 * 1 * 15))) / 2$

$x = (10 +- sqrt(40)) / 2$

$x = (10 +- 2sqrt10) / 2 = 5 +- sqrt10$

$x_+ = 5 + sqrt10, x_- = 5 - sqrt10$

How do you solve x^2-10x+15=0x^2-10x+15=0 using the quadratic formula?