What is the discriminant of $x^{2} + 2 x + 8 = 0$ $x^2+2x+8=0$ ?

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Answer 1 · 2014-09-11T05:27:03

Discriminant $\to b^{2} - 4 a c$ $->b^2-4ac$

$a = 1$ $a=1$
$b = 2$ $b=2$
$c = 8$ $c=8$

$b^{2} - 4 a c \to {(2)}^{2} - 4 (1) (8)$ $b^2-4ac->(2)^2-4(1)(8)$

$4 - 32 = - 28$ $4-32=-28$

Because the Discriminant is less than 0 we know that we have 2 complex roots.

Please see the following link on how to find the discriminant.

What is the discriminant of x^2+2x+8=0x2+2x+8=0x^2+2x+8=0?