How do you solve the quadratic using the quadratic formula given $2v^2-5v+3=0$ ?

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Answer 1 · 2018-05-22T21:53:00

v=1.5 or 1

$v=[-(-5)\pmsqrt((-5)^2-4xx2xx3)]/(2xx2)$

$v=[5\pmsqrt(25-24)]/(4)$

$v=(5+1)/4 or (5-1)/4$

$v=6/4 or 4/4$

$v=3/2 or 1$

How do you solve the quadratic using the quadratic formula given 2v^2-5v+3=02v^2-5v+3=0?