How do you find the extrema for $f (x) = \frac{e^{10 x}}{1 + e^{10 x}}$ $f(x)= (e^(10x))/(1+ e^(10x))$ for [-5,5]?

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Answer 1 · 2015-05-12T13:00:29

Have a look:
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graph{e^(10x)/(1+e^(10x)) [-6.243, 6.24, -3.12, 3.123]}

How do you find the extrema for f(x)= (e^(10x))/(1+ e^(10x))f(x)=e10x1+e10xf(x)= (e^(10x))/(1+ e^(10x)) for [-5,5]?